Secret Space Program Update - TR-3B (Space Ship) Patent Is Now In The Public Domain

Publication number US20060145019 A1
Publication type Application
Application number US 11/017,093
Publication date Jul 6, 2006
Filing date Dec 20, 2004
Priority date Dec 20, 2004
Inventors John St. Clair
Original Assignee St Clair John Q
Export Citation BiBTeX, EndNote, RefMan
External Links: USPTO, USPTO Assignment, Espacenet
Triangular spacecraft
US 20060145019 A1
Abstract
A spacecraft having a triangular hull with vertical electrostatic line charges on each corner that produce a horizontal electric field parallel to the sides of the hull. This field, interacting with a plane wave emitted by antennas on the side of the hull, generates a force per volume combining both lift and propulsion.
Images(8)
Claims(4)
1. A spacecraft comprised of the following components:
(a) a triangular hull in the form of an equilateral triangle;
(b) two copper plates attached on opposite vertical sides at each of the three corners of the hull (1 a) such that a sharp vertical edge is formed where they come together;
(c) an electrostatic generator used to charge the back two copper-cladded corners (1 b) to a high positive voltage, and the third forward copper-cladded corner to a high negative voltage;
(d) a horizontal slot antenna array mounted-on the sides of the hull; and
(e) a frequency generator, antenna and coaxial cables to drive the antenna array (1 d).
2. To create, by claims (1 a, 1 b, 1 c), an intense vertical line charge at the corners (1 b) and a horizontal electric field that that is parallel to the sides of the hull (1 a);
3. To create, by claims (1 d,1 e), an electromagnetic wave with a vertically polarized electric field traveling outward from the side of the hull (1 a); and
4. To create, by claims (2,3), an interaction of the electrostatic field (2) with the electromagnetic wave (3) such that a combined spacetime curvature pressure is generated on the hull in the upward and forward direction to produce lift and propulsion respectively.
Description
  • BRIEF SUMMARY OF THE INVENTION
  • [0001]
    This invention is a spacecraft having a triangular hull with vertical electrostatic line charges on each corner. The line charges create a horizontal electric field that, together with a plane wave emitted by antennas on the side of the hull, generates a force per volume providing a unique combination of both lift and propulsion.
  • BACKGROUND OF THE INVENTION
  • [0002]
    Referring to FIG. 1, the spacecraft has a hull in the shape of an equilateral triangle. A parabolic antenna (E) is centrally located in the bottom of the hull. An array of horizontal slot antennas is located along the side of the hull (A). Each back corner (F,G) has a corner conducting plate which is charged to a positive voltage +V. The forward corner (C) has a conducting plate charged to a negative voltage −V. A motion control hemisphere (D) is located on the bottom surface in each of the three corners.
  • [0003]
    Referring to FIG. 2, two planes (A,B) intersect at the origin O at an opening angle β. Each plane (x,y) is charged to a voltage V. The potential at point P is determined in polar coordinates {ρφ}. The Laplace equation for the potential Φ in polar coordinates is given by:
    1 ρ ⁢ ∂ ∂ ρ ⁢ ( ρ ⁢ ∂ Φ ∂ ρ ) + 1 ρ 2 ⁢ ∂ 2 ⁢ Φ ∂ ϕ 2 = 0
    Using a separation of variables solution, the potential is given as the product of two functions:
    Φ(ρ,φ)=R(ρ)Ψ(φ)
    which when substituted into the Laplace equation becomes:
    ρ R ⁢ ⅆ ⅆ ρ ⁢ ( ρ ⁢ ⅆ R ⅆ ρ ) + 1 Ψ ⁢ ⅆ 2 ⁢ Ψ ⅆ ϕ 2 = 0
    Since the two terns are separately functions of ρ and φ respectively, each one has to be constant with the sum of the constants equal to zero:
    ρ R ⁢ ⅆ ⅆ ρ ⁢ ( ρ ⁢ ⅆ R ⅆ ρ ) = v 2 ⁢   ⁢ 1 Ψ ⁢ ⅆ 2 ⁢ Ψ ⅆ ϕ 2 = - v 2
    These two equations have solutions:
    R(ρ)= v+bρ −v
    ψ(φ)=Acos(vφ)+Bsin(vφ)
    The azimuthal angle φ is restricted to a value in the range 0≦φ≦β. The boundary condition is that the potential Φ is equal to V for any radius ρ when φ=0 and φ=β. This means that v has to be an integer value of π so that the sine function is zero:
    sin ⁡ ( v ⁢   ⁢ β ) = sin ⁡ ( m ⁢   ⁢ π β ⁢ β ) = sin ⁡ ( m ⁢   ⁢ π ) = 0 ⁢   ⁢ m = 1 , 2 ⁢   ⁢ …
    which in turn means that the coefficient A of the cosine term has to be zero in the solution above. Choosing b=0 makes the general solution for the potential equal to:
    Φ ⁡ ( ρ , ϕ ) = V + ∑ m = 1 ∞ ⁢ a m ⁢ ρ m ⁢   ⁢ π / β ⁢ sin ⁡ ( m ⁢   ⁢ πϕ / β )
    which shows that when the angle is zero, the sine is zero and the potential is V. If the angle is β, then there is a multiple of π such that the sine is zero again.
  • [0004]
    Because the series involves positive powers of the radius, for small enough ρ, only the first term m=1 in the series is important. Thus around ρ=0, the potential is approximately
    φ(ρ,φ)≈V+aπ/βsin(πφ/β)
  • [0005]
    The electric field component is the negative gradient of the potential:
    E ϕ ⁡ ( ρ , ϕ ) = - 1 ρ ⁢ ∂ Φ ∂ ϕ = - π ⁢   ⁢ a 1 β ⁢ ρ ( π / β ) - 1 ⁢ cos ⁡ ( πϕ / β )
    The surface charge distribution σ at φ=0 and φ=β is equal to the electric field perpendicular to the surface times the permittivity of space ε0:
    σ ⁡ ( ρ ) = ɛ 0 ⁢ E ϕ ⁡ ( ρ , 0 ) = - ɛ 0 ⁢ π ⁢   ⁢ a 1 β ⁢ ρ π β - 1
    Notice that if angle of intersection β is less than π, then the equation says that there is a very small radius to a positive power which means little charge density accumulation.
  • [0006]
    Referring to FIG. 3, the value of β, in the case of the triangular hull, is equal to 360° less 60° for a total of 300° or:
    β = 300 180 ⁢ π = 5 3 ⁢ π ρ π 5 3 ⁢ π - 1 = 1 ρ 2 5
    which says that there is a charge density singularity to the two fifths power for small radius. Thus, the corner plates on the hull create a huge line charge density along the sharp vertical corner edge. The equation for the potential of a line charge density is given as:
    Φ ⁡ ( x , y ) = - λ 2 ⁢ πɛ 0 ⁢ Ln ⁡ ( ( x - x 0 ) 2 + ( y - y 0 ) 2 )
    where λ is the charge per unit length in the vertical z-direction, and x0 and y0 are the location of the line charge in the xy-plane.
  • [0007]
    Referring to FIG. 4, the triangular hull (D) is plotted together with the potential contours (A) and the electric field arrows (B) created by the three corner line charges. The line charges are perpendicular to the paper. Notice that the electric field arrows are parallel crossing the center parabolic antenna (C). The electric field is also parallel to the sides (D) of the triangle.
  • [0008]
    Referring to FIG. 5, along the side of the triangle (A), an array (B) of horizontal slot antennas emit electromagnetic waves that have a vertically polarized electric E field (C). These traveling waves interact with the electric field (D) produced by the line charges on the corners of the triangle.
  • [0009]
    Using differential forms mathematics, this combination of fields is represented by the Hodge star of the differential of the wedge product of the two fields. The antenna electromagnetic field is a combination of a traveling magnetic field Bw, and electric field Ew. The stationary field E created by the line charges is perpendicular to the traveling wave.
    * d ⁡ ( E ⋀ ( B w + E w ⋀ dt ) ) ⁢ ɛ c = force volume
    where ε is the linear capacitance of space and c is the speed of light. Thus there is a force per volume around the hull.
  • [0010]
    This combination of fields produces a spacetime curvature as determined by Einstein's General Theory of Relativity. The traveling electric field has an amplitude in the vertical z-direction and travels in the x-direction
    E w=E zcos(x−t)
    The Faraday electromagnetic tensor contains all the electric and magnetic fields in all the {x,y,z} directions. The first row and first column contain the two electric fields
    F β α = t x y z ⁢  0 E x 0 E z ⁢ cos ⁡ ( x - t ) E x 0 0 0 0 0 0 0 E z ⁢ cos ⁡ ( x - t ) 0 0 0 
    The stress exerted on spacetime occurs in the xx, yy and zz-direction as calculated from the stress-energy tensor T of gravitational physics
    4 ⁢ π ⁢   ⁢ T μ ⁢   ⁢ v = F μ ⁢   ⁢ α ⁢ F α μ - 1 4 ⁢ g μ ⁢   ⁢ v ⁢ F α ⁢   ⁢ β ⁢ F αβ
    where g is the metric tensor for Cartesian space
    g αβ = t x y z ⁢  - 1 0 0 0 0 1 0 0 0 0 1 0 0 0 0 1 
    where the diagonal components are the coefficients of the elementary spacetime length ds squared
    (ds)2=−(dt)2+(dx)2+(dy)2+(dz)2
    The calculation produces three stresses Txx,Tyy and Tzz in their respective {x,y,z} directions.
  • [0011]
    Referring to FIG. 6, these three stresses are plotted together as a 3D vector field animated over time in nine frames. The graphs show that there is a lift force as depicted by the vertical arrows as well as a force of propulsion as shown by the interspersed horizontal arrows. With the passage of time, these vectors exchange places with each other so that the lift becomes the propulsion and vice versa, creating a wavy stress-energy field around the hull.
  • SUMMARY OF THE INVENTION
  • [0012]
    This invention is a spacecraft with a triangular hull having charged flat plates on the vertical corners of the three sides. The two rear corners are charged to a potential V. The forward corner is charged to a potential −V. The 60° angle on the corner creates a line charge density singularity that produces a huge horizontal electric field pointing from the back to the front of the craft which is also parallel to the sides of the triangle. An array of horizontal slot antennas located on the sides of the triangular hull produce an electromagnetic wave with the electric field polarized in the vertical direction. This combination of fields produces a spacetime force in both the vertical and horizontal directions such that the spacecraft receives a lift force and a force of propulsion.
  • A BRIEF DESCRIPTION OF THE DRAWINGS
  • [0013]
    FIG. 1. Perspective view of triangular spacecraft.
  • [0014]
    FIG. 2. Drawing of the intersection of two charged plates in order to calculate the charge density in the corner.
  • [0015]
    FIG. 3. Perspective view of the corner angle β for the equilateral triangle.
  • [0016]
    FIG. 4. Planar 2D graph showing the electric field produced by three line charges on the corners of the triangular hull.
  • [0017]
    FIG. 5. Perspective view of electric field produced by the linear charge interacting with the traveling electromagnetic wave produced by the slot antenna.
  • [0018]
    FIG. 6. 3D vector animation of the lift and thrust force generated by the fields.
  • [0019]
    FIG. 7. Perspective view of slot antenna.
  • DETAILED DESCRIPTION OF THE INVENTION
  • [0020]
    Referring to FIG. 7, the antenna (A) is made out of sheet copper in which a rectangular horizontal slot (B) has been notched out using a die press and sheet metal fixture. A coaxial cable from the amplifier and frequency generator is attached across the slot by soldering the outer cable (D) to one side of the slot and the inner cable (E) to the other side of the slot. This creates the positive and negative charges across the gap which forms the vertical electric field (F) which radiates out perpendicularly to the copper sheet.
  • [0021]
    Although the invention has been described with reference to specific embodiments, such as a particular antenna system, those skilled in the art will appreciate that many modifications and variations are possible without departing from the teachings of the invention. All such modifications and variations are intended to be encompassed within the scope of the following claims.
Patent Citations
Cited Patent Filing date Publication date Applicant Title
US3675879 * Sep 2, 1969 Jul 11, 1972 Fuchs Harry B Method and means for creating artificial gravity in spacecraft
US5269482 * Sep 30, 1991 Dec 14, 1993 Shearing Ernest J Protective enclosure apparatus for magnetic propulsion space vehicle
US6974110 * Dec 27, 2002 Dec 13, 2005 Peter Grandics Method and apparatus for converting electrostatic potential energy
US20030209635 * May 9, 2002 Nov 13, 2003 St. Clair John Quincy Electric dipole moment propulsion system
US20030209637 * May 9, 2002 Nov 13, 2003 St. Clair John Quincy Rotating electrostatic propulsion system
US20060038081 * Aug 4, 2004 Feb 23, 2006 St Clair John Q Electric dipole spacecraft
Classifications
U.S. Classification 244/171.5
International Classification

B64G1/40

Clasiification B64G1/409
European Classification B64G1/40Z

B64G1/40

Patent Source

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Ive seen this with my own eyes  - it sailed quietly across Kaikoura one evening. We dubbed it Prince Harry's  Party Bus - as it was seen at the time his Highness was gracing NZ with his presence.

This contraption looks awfully familiar. The name Eugeny Podklektnov comes to my mind and the name "Electrogravitic Lifter".

I will hunt it down.

These are small unmanned thingies that I remember and very simple in construction. I'm almost certain I've seen them demo'd on Youtube.

Here ya go: One of many home built triangular "lifters" demonstrated:

https://www.youtube.com/watch?v=GXeBivOliI0

 pretty comprehensive overview of the whole TR3-A and TR3-B story:

http://tr3aurora.blogspot.co.nz/2013/02/exposed-usafs-tr-3-aurora.h...!/2013/02/exposed-usafs-tr-3-aurora.html

Awewsome!

Thanks Martin, ( and Rose for this discussion )... fascinating, with excellent diagrams and illustrations.

Personally, even though I've been a sky-watcher since childhood, I don't recall seeing anything this triangular in the sky, but always keeping my eyes peeled for any anomalies!

I remember telling Ian I spotted one of these over our house in Dallington one night with a university educated mate with a masters who couldn't explain what he was seeing then a month later I spotted three off the coast of New Brighton so I called him to go have a look telling him I thought they were experimental aircraft the one world order were in the final stages of development. That went down like a lead balloon with him but to this day he still cant provide an explanation of what we saw. The day we saw the three they were hovering in the air while doing complex manouvers around each other and Ian thought I had smoked to much whacky backy on those occasions intill he started to spot strange unexplainable objects after the Christchurch quakes. Like the stealth technology, we plebs don't get to find out until about 30 years after they develop it.

I thought I'd smoked to much whacky backy on those occasions to Lee.

The best evidence for these triangles comes from the "Belgian wave" of the 1980s and early 90s.

It's interesting to pursue the history of the "TR3-B" mythology. It was initially referred to as the "Northrop F121", until Popular Mechanics Magazine showed a speculative illustration of a clandestine Technical Reconnaisance  Aircraft: The TR3-A "Manta" built (allegedly) by Lockheed Martin. UFO researchers immediately pounced on this to speculate that the triangular aircraft being seen hovering around Eauropean skies was an advanced version, the TR3-B.

In actual fact, a triangular aircraft was indeed being developed at that time, the US Navy A12 Avenger, but it was a conventional jet. The fabled hypersonic Aurora, we now know, is the Lockheed Falcon Bomber UAV (which was accurately described by John Lear years before it became public knowledge). Another candidate for the Flying Triangle sightings was ASTRA, which was probably the "real" TR3-A never revealed to the public officially.

The most likely culprit for the silent, hovering, triangles, in my own opinion, is in fact not US technology at all, but British! BAE has had a low-key antigravity research department on the go for quite some time, close to Orford Ness and Porton Downs research facility. The codename is HALO: High Agility Low Observability, and may well be the identity of the triangular vehicle that caused such a fuss at Bentwaters USAFB on British soil when encounterd by US airmen on the ground at Rendlesham Forest. What better way to test British Psychotronic Stealth tech than on their unwitting US allies?

If the designation TR3-B is correct, on the other hand, then it's old or obsolete, as the "B" designation in a USAF aircraft denotes it's retirement from active service!

Perhaps that's why Price Harry came to mind when I saw it. I still reckon he was up there having a drive by his new real estate while entertaining his buddies in a flying nightclub. Harry probably picked it up in a Military auction when it became obsolete.

Hehehe

Great Scott! I think you have the answer there Rose

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